**721. Yalmaz can cover a distance of 400 metres in 2 minutes. Rayan can cover 1 km in 300 seconds. Find the ratio of their speeds.**

A. 2:5

B. 4:3

C. 1:2**D. 1:1**

**Explanation:****Rayan’s speed = 1000/300 = 3.33 m/s****Hence Ratio = 1:1**

**722. If the ratio of the speeds of A and B to cover a distance of 200 m is 3:4, then the ratio of the time taken to cover the same distance is________?**

A. 6:8

B. 3:7

C. 5:4**D. 4:3**

**Explanation:****If the ratio of the speeds of two objects is a:b, then the time taken by them to cover the same distance is****b:a Hence, the answer is 4:3**

**723. A car can travel 360km with a ¾ full tank. How many km can it travel with a 2/3 full tank?**

A. 400**B. 320**

C. 240

D. 300

**Explanation:****With a full tank, it can travel****360*4/3 = 480 km With 2/3 full tank, it can travel****480*2/3 = 320 km**

**724. A boats man can row in still water at speed of 7 km/hr. It takes 6 hours more to travel the same distance in upstream than in downstream if the speed of the river is 3 km/hr. what is the distance between the two destinations?**

A. 20 km**B. 40 km**

C. 30 km

D. 10 km

**Explanation:****x = 7 km/hr ; y = 3 km/hr****Ds = 10 km/hr ; Us = 4 km/hr****Distance (d) is same. Therefore, if time taken for downstream is t hours, the time for upstream is (t + 6) hours.****10*t = 4*(t + 6)****6t = 24 ; t = 4 hours****d = 10*4 = 40 km**

**725. If Afnan drives at 4/5th of his usual speed to his office, he is 6 minutes late. What is his usual time to reach his office?**

A. 36**B. 24**

C. 30

D. 18

**Explanation:****Let t be his usual time to reach his office and v be his usual speed.****v = d/t ……….(d is the distance Afnan travels while going to his office)****vt = d****At v1 = 4v/5 ; t1 = t + 6****4v/5 = d/(t + 6)****4v/5* (t + 6) = d****4v/5* (t + 6) = vt****On solving we get,****t = 24 minutes**

**726. Two boys starts from the same place walking at the rate of 5 kmph and 5.5 kmph respectively in the same direction. What time will they take to be 8.5 km apart?****A. 17 hr**

B. 14 hr

C. 12 hr

D. 19 hr

**Explanation:****Relative speed = 5.5 – 5 = .5 kmph (because they walk in the same direction)****distance = 8.5 km****time = distance/speed=8.5/.5=17 hr**

**727. A cyclist covers a certain distance in 50 minutes at a speed of 24 kmph. To cover the same distance in 40 minutes, he should travel at a speed of__________?****A. 30 kmph**

B. 27 kmph

C. 25 kmph

D. 20 kmph

**Explanation:****Distance = 24*50/60 = 20 km New Speed = 20/(40/60)) = 30 kmph**

**728. Excluding stoppages, the average speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?**

A. 9**B. 10**

C. 12

D. 20

**Explanation:****Due to stoppages, the bus travels only 45 kms in an hour (9 kms less). To cover a distance of 9 km at a speed of 54 kmph, time taken****= 9/54 = 1/6 hrs = 10 mins.**

**729. If a boat is rowed downstream for 50 km in 5 hours and upstream for 24 km in 6 hours, what is the speed of the boat and the river?****A. (7 , 3) km/hr**

B. (6 , 4) km/hr

C. (10 , 4) km/hr

D. None of these

**Explanation:****If x: speed of boats man in still water****y: speed of the river****Downstream speed (Ds) = x + y****Upstream speed (Us) = x – y****x = (Ds + Us) / 2****y = (Ds – Us) / 2****In the above problem Ds = 10 ; Us = 4****x = (10 + 4) / 2 = 14/2 = 7 km/hr****y = (10 – 4)/2 = 6/2 = 3 km/hr**

**730. Taimoor left for his school at 6 am by foot and walked at the rate of 2 kmph. After reaching his school he found it was closed and immediately turned back and started walking back to his home at 3 kmph. If he reached his home at 9 am, find the distance between his school and his home.**

A. 2.5 km

B. 7.2 km

C. 7 km**D. 3.6 km**

**Explanation:****Average speed of Taimoor = (2*2*3)/(2 + 3) = 2.4 km/hr****If d is he distance between the school and Taimoor’s home, then total distance walked by Taimoor = 2d, and the total time taken is 3 hours****2.4 = 2d/3****7.2 = 2d****d = 3.6 km**