**561. The difference between a number and its two-fifth is 510. What is 10% of that number?**

A. 12.75**B. 85**

C. 204

D. None of these

**Explanation:**

Let the number be x. Then,

x – 2/5 x = 510

x = (510 * 5)/3 = 850

10% of 850 = 85.

**562. Two-fifth of one-third of three-seventh of a number is 15. What is 40% of that number?**

A. 72

B. 84

C. 136

D. 140**E. None of these**

**Explanation:**

Let the number be x. Then,

2/5 of 1/3 of 3/7 of

x = 15 => x = (15 * 5/3 * 3 * 5/2) = 525/2

40% of 525/2 = (40/100 * 525/2) = 105

**563. If 20% of a number, then 120% of that number will be_________?**

A. 20

B. 120

C. 360**D. 720**

**Explanation:**

Let the number x. Then,

20% of x = 120

x = (120 * 100)/20 = 600

120% of x = (120/100 * 600) = 720.

**564. 45% of 750 – 25% of 480 =__________?**

A. 216**B. 217.50**

C. 236.50

D. 245

**Explanation:**

Given expression = (45/100 * 750) – (25/100 * 480) = (337.50 – 120) = 217.50

**565. 3.5 can be expressed in terms of percentage as?**

A. 0.35%

B. 3.5%

C. 35%**D. 350%**

**Explanation:**

3.5 = 35/10 = (35/10 * 100) = 350%

**566. The ratio of the prices of three articles X, Y and Z is 8 : 5 : 3. If the prices of X , Y and Z are increased by 25%, 20% and 33 1/3% respectively, then what would be the ratio of the new prices of X, Y and Z?**

A. 5 : 3 : 1**B. 5 : 3 : 2**

C. 10 : 7 : 4

D. 10 : 8 : 5

E. None of these

**Explanation:**

Let the prices of X, Y and Z be 8k, 5k and 3k respectively.

After increase

Price of X = 8k * 125/100 = 10k

Price of Y = 5k * 120/100 = 6k

Price of Z = 3k * (133 1/3)/100 = 4k

Required ratio = 10k : 6k : 4k = 5 : 3 : 2

**567. Two tests had the same maximum mark. The pass percentages in the first and the second test were 40% and 45% respectively. A candidate scored 216 marks in the second test and failed by 36 marks in that test. Find the pass mark in the first test?**

A. 136

B. 128

C. 164

D. 214**E. None of these**

**Explanation:**

Let the maximum mark in each test be M.

The candidate failed by 36 marks in the second test.

pass mark in the second test = 216 + 36 = 252

45/100 M = 252

Pass mark in the first test = 40/100 M = 40/45 * 252 = 224.

**568. In an election between two candidates A and B, the number of valid votes received by A exceeds those received by B by 15% of the total number of votes polled. If 20% of the votes polled were invalid and a total of 8720 votes were polled, then how many valid votes did B get?**

A. 2160

B. 2420**C. 2834**

D. 3150

E. None of these

**Explanation:**

Let the total number of votes polled in the election be 100k.

Number of valid votes = 100k – 20% (100k) = 80k

Let the number of votes polled in favour of A and B be a and b respectively.

a – b = 15% (100k) => a = b + 15k

=> a + b = b + 15k + b

Now, 2b + 15k = 80k and hence b = 32.5k

It is given that 100k = 8720

32.5k = 32.5k/100k * 8720 = 2834

The number of valid votes polled in favor of B is 2834.

**569. In an office, totally there are 6400 employees and 65% of the total employees are males. 25% of the males in the office are at-least 50 years old. Find the number of males aged below 50 years?**

A. 1040

B. 2080**C. 3120**

D. 4160

E. None of these

**Explanation:**

Number of male employees = 6400 * 65/100 = 4160

Required number of male employees who are less than 50 years old = 4160 * (100 – 25)%

= 4160 * 75/100 = 3120.

**570. The monthly incomes of A and B are in the ratio 5 : 2. B’s monthly income is 12% more than C’s monthly income. If C’s monthly income is Rs. 15000, then find the annual income of A?**

A. Rs. 420000

B. Rs. 180000

C. Rs. 201600**D. Rs. 504000**

E. None of these

**Explanation:**

B’s monthly income = 15000 * 112/100 = Rs. 16800

B’s monthly income = 2 parts —-> Rs. 16800

A’s monthly income = 5 parts = 5/2 * 16800 = Rs. 42000

A’s annual income = Rs. 42000 * 12 = Rs. 504000