**641. How much 60% of 50 is greater than 40% of 30?****A. 18**

B. 13

C. 15

D. 20

**Explanation:****(60/100) * 50 – (40/100) * 30****30 – 12 = 18**

**642. After decreasing 24% in the price of an article costs Rs.912. Find the actual cost of an article?**

A. 1400

B. 1300**C. 1200**

D. 1100

**Explanation:****CP* (76/100) = 912****CP= 12 * 100 => CP = 1200**

**643. If y exceeds x by 20%, then x is less than y by_______?**

A. 16%

B. 16 1/3 %**C. 16 2/3 %**

D. 16 3/5 %

**Explanation:****X=100 y=120****120——20****100——-? => 16 2/3%**

**644. What percent of 120 are 90?**

A. 25%

B. 50%**C. 75%**

D. 33%

**Explanation:****(?% /100) * 120 = 90****? = 75%**

**645. Today is khadija’s birthday. After one year, she will become two times as she was ten years ago. current age of Khadija?**

A. 19

B. 20**C. 21**

D. 22

**Explanation:****let her age be x****after 1 year her age will be x+1=2(x-10)****x+1=2x-20****1+20=2x-x****x=21 years**

**646. In what ratio should the profit be divided if M, N, O invests capital in ratio 2:3:5 and their timing of their investments are in the ratio 4:5:6.****A. 8:15:30**

B. 5:18:28

C. 4:5:6

D. 2:3:5

**Explanation:****P1:P2:P3 = (2*4):(3*5):(5*6)****= 8 : 15 : 30**

**647. A bag contains 50 paise, 1 rupee and 2 rupee coins in the ratio 2:5:8. If the total amount is Rs. 352, find the total number of coins in the bag.**

A. 160

B. 200

C. 250**D. 240**

**Explanation:****Let the number of 50p, 1 rupee and 2 rupee coins be 2x,5x and 8x. 0.5*(2x)+5x+2*8x = 352 22x=352 x=16 Total no. of coins****= 2x+5x+8x****= 15x = 240**

**648. Three quantities X, Y and Z are such that XY=kZ where k is constant. Initially, X was at 4 and X:Y:Z was 2:3:4. If the value of Y is changed to 12 and Z is kept constant, find the value of X.****A. 2**

B. 3

C. 5

D. 6

**Explanation:****X:Y:Z=2:3:4****X=4****Then, Y=6, Z=8 XY=kZ 4*6=k*8 8k=24 k=3****Y=12, Z=8****X*12=3*8****X=2**

**649. Find the mean proportion between 5 and 45.**

A. 9**B. 15**

C. 25

D. 50

**Explanation:****5:x::x:45 x²=45*5 = 225 x=15**

**650. If X:Y = 2:3, Y:Z = 4:5. Find X:Y:Z.**

A. 2:3:5**B. 8:12:15**

C. 2:8:5

D. 2:7:5

**Explanation:****If A:B = m1:n1 ; B:C = m2:n2****Then, A:B:C = (m1*m2):(n1*m2):(n1*n2)****Therefore, X:Y:Z = (2*4):(3*4):(3*5)****= 8:12:15**

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