661. A bag contains 1 rupee, 2 rupee and 5 rupee coins amounting to Rs.264. If the ratio of the number of these coins is 3:5:4, find the number of 1 rupee coins.
A. 66
B. 48
C. 24
D. 8

Explanation:
Let the number of 1 rupee, 2 rupee and 5 rupee coins be 3x, 5x and 4x. (1*3x)+(2*5x)+(5*4x)=264 3x+10x+20x=264 33x=264 x=8 No. of 1 rupee coins
= 3x = 24

662. Divide Rs.2000 into two shares in the ratio 3:2.
A. Rs.1200,Rs.800
B. Rs.800,Rs.1200
C. Rs.1500,Rs.500
D. Rs.1100, Rs.900

Explanation:
3x+2x=2000 5x=2000 x=400 3x=1200 2x=800

663. The ratio of two numbers is 5:9. If each number is decreased by 5, the ratio becomes 5:11. Find the numbers.
A. 30, 19
B. 21, 37
C. 15, 34
D. 15, 27

Explanation:
Let the two numbers be 5x and 9x.
(5x-5)/(9x-5) = 5:11
(5x-5)*11 = (9x-5)*5
55x – 55 = 45x – 25
10x = 30
x = 3
Therefore, the numbers are 15 and 27.

664. The third proportional to 3.5, 5.6 is:___________?
A. 8.96
B. 8
C. 4.5
D. 6.2

Explanation:
3.5/5/6 = 5.6/x ; x = 5.6 * 5.6 / 3.5 = 8.96

665.mAccording to a recipe, 400 grams of flour should be mixed with 500 grams of sugar to bake cookies. If I have only 300 grams of flour, how much sugar should I mix to maintain the same proportion?
A. 360
B. 380
C. 375
D. 400

Explanation:
Flour and sugar have to mixed in the ratio 4:5 4:5::300:x 4x=1500 x=375 375 grams of sugar should be mixed.

666. X, Y and Z are quantities of the same kind such that X:Y=5:8 and Y:Z=4:7. Find X:Z.
A. 32:35
B. 67:56
C. 5:14
D. 5:7

Explanation:
X:Z=(X:Y)*(Y:Z) =(5:8)*(4:7) = (5/8)*(4/7) = 5/14

667. Two kinds of rice, 1st costs Rs.13 per kg and 2nd costs Rs.19 per kg are mixed together. Find the ratio in which the 2 types are mixed so that the mixture costs Rs.14.2 per kg?
A. 3:1
B. 4:1
C. 3:4
D. 4:3

Explanation:
Let the total quantity of mixture be 1. If quantity of 1st type is x then quantity of the 2nd type will be (1-x)
Therefore, 13x + 19(1-x) = 14.2
13x -19x + 19 = 14.2
4.8 = 6x
x = 0.8 ; (1-x) = 0.2
Therefore, the ratio is 0.8 : 0.2 = 4:1

668. A, B, C and D divide a sum of money among themselves in the ratio 7:4:3:2. If D gets Rs. 500 less than A, find the total amount.
A. Rs.100
B. Rs.700
C. Rs.1600
D. Rs.2000

Explanation:
Let the amount be divided into 7x,4x,3x and 2x.
7x-2x = 500 5x=500 x = 100
Total amount = 7x+4x+3x+2x = 16x = Rs.1600

669. x is 20% more than z and y is 80% more than z. Find x:y.
A. 1:4
B. 3:4
C. 1:3
D. 2:3

Expanation:
x = z+(20/100)z = 1.2z y = 1.8z x:y = 1.2z:1.8z = 12:18 = 2:3

670. Solve for x
2x:25 = 6:(x/3)
A. 18
B. 15
C. 12
D. 5

Explanation:
2x/25 = 6/(x/3) 2x/25 = 18/x 2x*x = 18*25 x² = 9*25 x=3*5 x=15

NOTE
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